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Program to find Number of Digits in a Number's Factorial

#include <math.h> #include <stdio.h> void main() //can be replaced with int main, i prefer void main {     int i =1,j;     printf("Enter the Number: ");     scanf("%d",&j);     double k = 0,l = log(10);     for(;i<=j;i++)   {         k = k + (log(i)/l);     }     k = (int) (k+0.5);     printf("\n NOD: %f",k+1); } Source:   http://inder-gnu.blogspot.com/2009/09/find-number-of-digits-in-number.html